So total possibility will be equal to four before I can't write that is nothing but four factorial. So we have total four elements and we have to create the string having four elements. Now we have a total of one do three and 4. Also you will have to take as one element. So abc would have to take that as one digit. We have adopted this total visits as total elements as A B C D E F, jesus RPG We have Now the question was asked to find the strings with A B, C and D. For example 45, when converted to binary, is 101101, when represented in BCD is 01000101. Now the next part of the question is the strings with abc and be so oh the available letters. BCD is different from converting a decimal number to binary. So the number of possibilities that we have with this BCD. I Googled BCD Java and got this as the first result. Surely someone out there has written a BCD conversion utility for Java. Five because five P five is nothing but five factorial and that will be equal to five factorial is 1 20. After, i have to read the BCD and convert it to the original string 0200 but first i have to resolve String to BCD. So total possibility will be equal to the door day possibility will be equal to five into four into three into two into one. Now we are reminding with four elements and this place I can fill with four different ways and this with three to this with one. The Hex/BCD to 7 Segment Display (SEG) instruction is used to convert a single four. I can fill this place and now we take 11 element for this first place. So this first place I can fill with five different ways because we have a total of five letters over here. Four sorry five P5 that is we have to find we have a total of five letters and we have to have a string having filed letters or in other words I can tell this like we have a total five digits and we have to make a string having five letters 12345. Now we have to find how how many preparations that is possible with five letters. We can take it as 11 element and the others as the remaining elements that is. So if B C D condemns in the string then this set B C D. So this we have to find the permutations that is having this B C D. We have now the question was asked to find how many permutations of these letters contain the strain B C B. So I'm just writing that available letters over here.
C string to bcd code#
Convert String from ASCII to EBCDIC in Java?įinally, if you really meant converting into another BCD format, you may have write your own code based the rules governing your specific BCD format.īefore you start coding, of course, I still recommend looking for libraries performing the conversion for you.So here the available letters are A B C D E F G.In such case I recommend checking the following StackOverflow question and its related answers: In the financial/services sector, for example, it's very common the need to convert into the EBCDIC format ( ) to interact with IBM systems. It is to be noted however that the above code will accept as inputs also strings containing letters up to the letter "F" so if that's not acceptable to you, you will have to make sure that your string only contains numbers.Īs BCD comprises a number of variants, I believe it's worth mentioning that before applying a BCD conversion you should determine which specific conversion you want to apply based on your software's purposes. In the interest of "not reinventing the wheel", however, I would favour functionality available in libraries like Apache Commons or Google Guava:įor Apache Commons it boils down to roughly this code: byte result = Hex.decodeHex(points) Convert a string representation of a hex dump to a byte array using Java?.There are solutions in StackOverflow, such as the following: Based on the code you provided and its expected output it looks like you're trying to convert into the BCD format (BCD is a rather generic definition) normally used to represent a string in which each letter represents a HEX digit into its corresponding byte representation (from comments to this answer: "packed BCD").
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